700x^2+300x=100

Solution for 700x^2+300x=100 equation:

700x^2+300x=100

We move all terms to the left:

700x^2+300x-(100)=0

a = 700; b = 300; c = -100;
Δ = b2-4ac
Δ = 3002-4·700·(-100)
Δ = 370000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{370000}=\sqrt{10000*37}=\sqrt{10000}*\sqrt{37}=100\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-100\sqrt{37}}{2*700}=\frac{-300-100\sqrt{37}}{1400}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+100\sqrt{37}}{2*700}=\frac{-300+100\sqrt{37}}{1400}
$